A) 1-propanol
B) 2-propanol
C) 1, 2-dihydroxypropane
D) n-propane
Correct Answer: A
Solution :
\[C{{H}_{3}}-CH=C{{H}_{2}}+{{(H-B{{H}_{2}})}_{2}}\xrightarrow{{}}\] \[C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}B{{H}_{2}}\xrightarrow{C{{H}_{3}}CH=C{{H}_{2}}}\] \[{{(C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}})}_{2}}BH\xrightarrow{C{{H}_{3}}CH=C{{H}_{2}}}\] \[{{(C{{H}_{3}}C{{H}_{2}}C{{H}_{2}})}_{3}}B\xrightarrow[O{{H}^{-}}]{{{H}_{2}}O,\,\,3{{H}_{2}}{{O}_{2}}}\] \[\underset{propan-1-ol}{\mathop{3C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}}}\,OH+B{{(OH)}_{3}}\]
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