question_answer

The unpaired electron in \[Ni{{(CO)}_{4}}\] is

A)  1                            

B)  2      

C)  3                            

D)  0

Correct Answer: D

Solution :

                In \[Ni{{(CO)}_{4}}\], there is no unpaired electron. It is diamagnetic. Oxidation state of Ni in \[[Ni{{(CO)}_{4}}]\] complex compound is zero. \[Ni=3{{d}^{8}}4{{s}^{2}}\]                 \[s{{p}^{3}}\] hybridised orbitals of Ni                                 \[[Ni{{(CO)}_{4}}]\]