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AMU Medical AMU Solved Paper-2013

  • question_answer
    1 mole of an ideal gas expands isothermally so that its pressure falls \[1.05\times {{10}^{5}}\] Pa to \[0.5\times {{10}^{5}}\] Pa. The change in entropy of the gas is equal to

    A)  0                                            

    B)  0.693 J/K

    C)  5.76 J/K             

    D)  None of these

    Correct Answer: C

    Solution :

                    Given that                 \[n=1\,mol\]                 \[{{p}_{1}}=1.0\times {{10}^{5}}Pa\]                 \[{{p}_{2}}=0.5\times {{10}^{5}}Pa\] Change in entropy of the gas                 \[=\frac{Q}{T}=\frac{W}{T}\]                 \[=\frac{nRT\log ({{p}_{1}}/{{p}_{2}})}{T}\]                 \[=nR\log ({{p}_{1}}/{{p}_{2}})\]                 \[=1\times 8.31\times 2.303\times 0.3010=5.76\,J/K\]


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