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AMU Medical AMU Solved Paper-2013

  • question_answer
    A 140 g ball, in horizontal flight with a speed \[{{\upsilon }_{1}}\]of 39.0 m/s, is struck by a bat. After leaving the bat, the ball travels in the opposite direction with speed \[{{\upsilon }_{2}}=39.0\,m/s\]. If the impact time \[\Delta t\] for the ball-bat collision is 1.20 ms, what average net force acts on the ball?

    A)  1308 N                                

    B)  1090 N

    C)  9100 N                

    D)  980 N

    Correct Answer: C

    Solution :

                    \[F=\frac{(m({{v}_{1}}-{{v}_{2}})}{t}\]                 \[=\frac{140\times {{10}^{-3}}(39+39)}{12\times {{10}^{-3}}}\]                 \[=\frac{1400\times 78}{12}\]                 = 9100 N


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