question_answer

The structure of diamagnetic nickel complex, \[{{[Ni{{(CN)}_{4}}]}^{2-}}\]is

A)  trigonal bipyramidal      

B)  tetrahedral

C)  square planar                  

D)  distorted octahedral

Correct Answer: C

Solution :

                 In \[{{[Ni{{(CN)}_{4}}]}^{2-}}\] , nickel is in +2 oxidation state and has electronic configuration 3d8. Orbitals of \[N{{i}^{2+}}\] ion                 \[ds{{p}^{2}}\] hybridised orbitals of \[N{{i}^{2+}}\]                 \[{{[Ni{{(CN)}_{4}}]}^{2-}}\] low spin complex                   Therefore, the shape is square planar and the hybridisation involved is \[ds{{p}^{2}}\].