A) \[{{C}_{6}}{{H}_{5}}COOH+C{{H}_{3}}OH\xrightarrow{{{H}^{+}}}\]
B) \[{{C}_{6}}{{H}_{5}}COOCl+C{{H}_{3}}OH\xrightarrow{Pyridine}\]
C) \[{{C}_{6}}{{H}_{5}}COOH+C{{H}_{2}}{{N}_{2}}\xrightarrow{{}}\]
D) All of the above methods
Correct Answer: D
Solution :
\[{{C}_{6}}{{H}_{5}}COOH+C{{H}_{3}}OH\xrightarrow{{{H}^{+}}}\]\[\underset{methyl\text{ }benzoate}{\mathop{{{C}_{6}}{{H}_{5}}COOHC{{H}_{3}}}}\,+{{H}_{2}}O\] (The reaction is known as Fischer - Sprier esterification reaction.) \[{{C}_{6}}{{H}_{5}}COCl+C{{H}_{3}}OH\xrightarrow{Pyridine}\]\[{{C}_{6}}{{H}_{5}}COOC{{H}_{3}}+HCl\] \[{{C}_{6}}{{H}_{5}}COOH+\,\,\underset{diazomethane}{\mathop{C{{H}_{2}}{{N}_{2}}}}\,\,\,\xrightarrow{{}}\]\[{{C}_{6}}{{H}_{5}}COOC{{H}_{3}}+{{N}_{2}}\] (Methyl easters can be prepared by treating carboxylic acid with ethereal solution of diazomethane. Hence, methyl benzoate can be prepared by all these above methods.
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