A) \[{{B}_{x}}=0,\,{{B}_{y}}=6.7\times {{10}^{-9}}\cos [\pi \times {{10}^{16}}(t-x/c)]\],\[{{B}_{z}}=0\]
B) \[{{B}_{x}}=0,\,{{B}_{y}}=-6.7\times {{10}^{-9}}\cos [\pi \times {{10}^{15}}(t-x/c)]\],\[{{B}_{z}}=0\]
C) \[{{B}_{x}}=0,\,{{B}_{y}}=0,\,{{B}_{z}}=2.0\cos [\pi \times {{10}^{15}}(t-x/c)]\]
D) \[{{B}_{x}}=0,\,{{B}_{y}}=0,\,{{B}_{z}}=-6.7\times {{10}^{-9}}\cos [\pi (t-x/c)]\]
Correct Answer: B
Solution :
At plane, electromagnetic wave travelling with velocity \[c=3\times {{10}^{8}}m/s\] along x-axis, then electric field vector E is along y-axis while the magnetic field vector is along z-axis \[{{B}_{x}}=0\]\[{{B}_{y}}=-\frac{{{E}_{z}}}{C}=\frac{2.0\cos [\pi \times {{10}^{15}}(t-x/c)]}{3\times {{10}^{8}}}\] \[{{B}_{y}}=-6.7\times {{10}^{-9}}\cos [\pi \times {{10}^{15}}\,\,\,(t-x/c)]\]\[{{B}_{2}}=0\]
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