A) +8
B) +5
C) +3
D) +1
Correct Answer: B
Solution :
\[R{{b}_{4}}Na[H{{V}_{10}}{{O}_{28}}]\] Let oxidation number of V is x. \[\therefore \] \[4\times 1+1+[+1+10x+28(-2)]=0\] or \[4+1+1+10x-56=0\] or \[x=+5\]You need to login to perform this action.
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