A) \[5.6\times {{10}^{10}}Hz\]
B) \[6.9\times {{10}^{12}}Hz\]
C) \[7.3\times {{10}^{13}}Hz\]
D) \[1.31\,\,\,{{10}^{15}}Hz\]
Correct Answer: B
Solution :
The given, \[\lambda =43470\,nm\] (for He atom) \[=43470\times {{10}^{-9}}m\] We know that, \[v=3\times {{10}^{8}}\,m/s\] (speed of the light) \[{{f}_{\min }}=?\] \[{{f}_{\min }}=\frac{V}{\lambda }=\frac{3\times {{10}^{8}}}{43470\times {{10}^{-9}}}=0.0000690\times {{10}^{17}}Hz\] \[=6.9\times {{10}^{12}}Hz\]
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