A) Volume / Density
B) Surface tension/\[{{\left( Angular\text{ }velocity \right)}^{2}}\]
C) Linear momentum / Force
D) Pressure / Power
Correct Answer: B
Solution :
Dimension of surface tension \[=\frac{force}{length}\] \[=\frac{[ML{{T}^{-2}}}{[L]}=[M{{L}^{0}}T{{}^{-2}}]\] Dimension of angular velocity \[=\frac{angle}{time}\] \[=\frac{[{{M}^{0}}{{L}^{0}}{{T}^{0}}]}{[T]}=[{{M}^{0}}{{L}^{0}}{{T}^{-1}}]\] So, \[\frac{surface\text{ }tension}{{{\left( angular\text{ }velocity \right)}^{2}}}\] \[=\frac{[M{{L}^{0}}{{T}^{-2}}]}{{{[{{M}^{0}}{{L}^{0}}{{T}^{-1}}]}^{2}}}=[M]\]
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