A) 9.0m
B) 6.0m
C) 4.0 m
D) 0.0 m
Correct Answer: A
Solution :
The given equation can be written as \[\sqrt{x}=t-3\] Squaring on both sides, we get, \[x={{t}^{2}}-6t+9\] Differentiating \[\frac{dx}{dt}=2\,t-6\] For 6 m/s velocity, we have \[6=2\,t-6\] \[t=6\,s\] At t = 6 s, the displacement is \[x={{t}^{2}}-6\,t+9\] \[x={{6}^{2}}-6\times 6+9\] \[x=9.0\,m\]You need to login to perform this action.
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