A) \[\frac{1}{2}M{{\omega }^{2}}L\]
B) \[M{{\omega }^{2}}L\]
C) \[\frac{1}{4}M{{\omega }^{2}}L\]
D) \[\frac{1}{6}M{{\omega }^{2}}L\]
Correct Answer: A
Solution :
The moment of inertia of a tube is \[=\frac{1}{2}ML\] The force exerted \[=\frac{1}{2}ML\times {{\omega }^{2}}=\frac{1}{2}M{{\omega }^{2}}L\]
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