A) \[4.1\times {{10}^{6}}N-{{m}^{2}}/C\]
B) \[1.3\times {{10}^{4}}N-{{m}^{2}}/C\]
C) \[-4.1\times {{10}^{6}}N-{{m}^{2}}/C\]
D) Zero
Correct Answer: A
Solution :
The given, \[R=0.6m,\,{{\varepsilon }_{0}}=8.85\times {{10}^{-12}}{{C}^{2}}{{N}^{-1}}{{m}^{-2}}\] \[\sigma =8.1\times {{10}^{-6}}C/{{m}^{2}}\] \[{{\phi }_{E}}=?\] The change on the sphere \[q=4\pi {{R}^{2}}.\,\sigma \] \[=4\times 3.14\times {{(0.6)}^{2}}\times 8.1\times {{10}^{-6}}\] \[=36.62\times {{10}^{-6}}C\] The total electric flux \[{{\phi }_{E}}=\frac{q}{{{\varepsilon }_{0}}}\] \[=\frac{36.62\times {{10}^{-6}}}{8.85\times {{10}^{-12}}}\] \[=\frac{36.62\times {{10}^{6}}}{8.85}\] \[=4.13\times {{10}^{6}}N-{{m}^{2}}/C\]
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