A) \[{{B}_{3}}{{N}_{3}}{{H}_{6}}\]
B) \[{{(B-N)}_{3}}\]
C) \[{{N}_{2}}{{H}_{4}}\]
D) \[BH_{4}^{-}\]
Correct Answer: A
Solution :
\[3{{B}_{2}}{{H}_{6}}+6N{{H}_{3}}\xrightarrow{{{200}^{o}}C}\underset{Borazine\text{ }or\text{ }borazole}{\mathop{2{{B}_{3}}{{N}_{3}}{{H}_{6}}+12{{H}_{2}}}}\,\]
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