A) \[1\,mL\,{{H}_{2}}{{O}_{2}}\] will give \[100\,mL\,{{O}_{2}}\] at STP
B) 1 L of \[{{H}_{2}}{{O}_{2}}\] will give \[100\,mL\,{{O}_{2}}\] at STP
C) 1 L of \[{{H}_{2}}{{O}_{2}}\] will give 22.4 L \[{{O}_{2}}\] at STP
D) 1 mL of \[{{H}_{2}}{{O}_{2}}\] will give 1 mole of \[{{O}_{2}}\] at STP
Correct Answer: A
Solution :
x volume \[{{H}_{2}}{{O}_{2}}\] means that 1 mL of \[{{H}_{2}}{{O}_{2}}\]at NTP gives x mL \[{{O}_{2}}\] gas.
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