AMU Medical AMU Solved Paper-2015

  • question_answer
    A circular loop of area 1\[c{{m}^{2}}\], carrying a current of 10 A is placed in a magnetic field of T perpendicular to the plane of the loop. The torque on the loop due to the magnetic field is

    A) zero                      

    B)                  \[{{10}^{-4}}N\,m\]

    C)   \[{{10}^{-2}}N\,m\]                      

    D)  1 Nm

    Correct Answer: A

    Solution :

                     Circular loop is placed perpendicular to the magnetic field. Therefore, angle between area vector and magnetic field is zero. \[\therefore \]  \[\tau =IAB\sin {{0}^{o}}=0\]


You need to login to perform this action.
You will be redirected in 3 sec spinner