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AMU Medical AMU Solved Paper-2015

  • question_answer
    A jet engine emits a sound of frequency 3000 Hz. When the engine is moving directly away from the observer at half the speed of sound (speed of sound = 340 m/s), the observer hears a sound of frequency

    A)  1000 Hz               

    B)  1500 Hz

    C)  2000 Hz               

    D)  4500 Hz

    Correct Answer: B

    Solution :

                    Frequency received by the observer                 \[v=v\left( \frac{v}{v+u} \right)=v\left( \frac{1}{1+\frac{u}{v}} \right)\]                 \[=3000\left( \frac{1}{1+\frac{1}{2}} \right)\]                 \[=300\frac{1}{3/2}\]                 \[=3000\times \frac{2}{3}\]                 = 2000 Hz


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