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AMU Medical AMU Solved Paper-2015

  • question_answer
    Two moles of an ideal gas are allowed to expand reversibly and isothermally at 300 K from a pressure of 1 atm to a pressure of 0.1 atm. The change in Gibbs free energy is

    A)                  -11.488J                              

    B)                  +11.488J

    C)  -11.488kJ                           

    D)  zero

    Correct Answer: C

    Solution :

                     Use the following equation,                 \[\Delta G=2303\,nRT\log \left( \frac{{{p}_{2}}}{{{p}_{1}}} \right)\] \[\therefore \]  \[\Delta G=2.303\times 2\times (8.314\,J\,{{K}^{-1}}mo{{l}^{-1}})\]                                 \[\times (300\,K)\times \log \left( \frac{0.1\,atm}{1\,atm} \right)\]                 = - 11488J                 = - 11.488 kJ


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