AMU Medical AMU Solved Paper-2015

  • question_answer
    What will be the angle of diffraction for the first secondary maximum due to diffraction at a single slit of width 0.4 mm, using light of wavelength 4000 Å?

    A)  \[1.0\times {{10}^{-4}}\] rad

    B)  \[0.5\times {{10}^{-4}}\] rad

    C)  \[0.15\times {{10}^{-3}}\] rad

    D)  \[1.5\times {{10}^{-3}}\] rad

    Correct Answer: D

    Solution :

                     Angle of diffraction for the secondary maxima                 \[\theta =\frac{3}{2}\times \frac{\lambda }{a}\]                 \[=\frac{3}{2}\times \frac{4000\times {{10}^{-10}}}{0.4\times {{10}^{-3}}}\]                 \[=\frac{30}{2}\times {{10}^{-4}}\]                 \[=15\times {{10}^{-4}}\]                 \[=1.5\times {{10}^{-3}}rad\]


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