A) parallel
B) perpendicular
C) concurrent
D) none of these
Correct Answer: C
Solution :
Given lines are \[(p-q)x(q-r)y+(r-p)=0\] \[(q-r)x+(r-p)y+(p-q)=0\] \[(r-p)x+(p-q)y+(q-r)=0\] Now, \[\Delta =\left| \begin{matrix} p-q & q-r & r-p \\ q-r & r-p & p-q \\ r-p & p-q & q-r \\ \end{matrix} \right|\] Applying \[{{C}_{1}}\to {{C}_{1}}+{{C}_{2}}+{{C}_{3}}\] \[=\left| \begin{matrix} 0 & q-r & r-p \\ 0 & r-p & p-q \\ 0 & p-q & q-r \\ \end{matrix} \right|\] \[=0\] \[\therefore \] Given lines are concurrent.
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