A) \[\frac{1}{{{\,}^{52}}{{C}_{4}}}\]
B) \[\frac{{{({{\,}^{13}}{{C}_{1}})}^{4}}}{{{\,}^{52}}{{C}_{4}}}\]
C) \[\frac{{{({{\,}^{13}}{{C}_{2}})}^{2}}}{{{\,}^{52}}{{C}_{4}}}\]
D) \[\frac{{{({{\,}^{13}}{{C}_{4}})}^{4}}}{{{\,}^{52}}{{C}_{4}}}\]
Correct Answer: B
Solution :
The total number of ways in which 4 cards can be selected out of 52 cards in \[{{\,}^{52}}{{C}_{4}}.\]There are four suits in a pack and in each suit contains 13 cards. Therefore the number of ways of selecting one card from each suit is \[{{({{\,}^{13}}{{C}_{1}})}^{4}}\] \[\therefore \]Required probability \[=\frac{({{\,}^{13}}{{C}_{1}})}{{{\,}^{52}}{{C}_{4}}}\]
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