A) \[\frac{3{{u}^{2}}}{g}\]
B) \[\frac{4{{u}^{2}}}{g}\]
C) \[\frac{6{{u}^{2}}}{g}\]
D) \[\frac{9{{u}^{2}}}{g}\]
Correct Answer: B
Solution :
Since, the stone thrown vertically, therefore initial velocity \[=u.\]final velocity \[=-3u\]and distance \[=-h\]using the relation \[{{v}^{2}}={{u}^{2}}-2gs\] \[\Rightarrow \] \[{{(-3u)}^{2}}={{u}^{2}}-2g(-h)\] \[\Rightarrow \] \[8{{u}^{2}}=2g\,h\] \[\Rightarrow \] \[h=\frac{4{{u}^{2}}}{g}\]
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