question_answer

The resultant of two like parallel forces is 12N. The distance between the forces is 18 m. If  one force is of 4N, then the distance of the resultant from the smaller force is:

A)  4 m                                       

B)  8 m                       

C)  12 m                    

D)         none of these

Correct Answer: C

Solution :

Since, one force is 4N, then the other force is \[12N-4N=8N\] Let the distance of the resultant from the smaller force is \[x.\] i.e., \[AC=x,\]then \[CB=18-x\] \[4.AC=8.BC\] \[\Rightarrow \]               \[AC=2BC\] \[\Rightarrow \]               \[x=2(18-x)\] \[\Rightarrow \]               \[3x=36\] \[\Rightarrow \]               \[x=12\,m\]