A) \[\text{11 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-4}}}\text{T}\]
B) \[\text{10 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-4}}}\text{T}\]
C) \[\text{0}\text{.1 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-4}}}\text{T}\]
D) \[\text{1 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-4}}}\text{T}\]
Correct Answer: D
Solution :
A magnetic charge (pole) placed in a magnetic field experiences a force \[F=mB\] Here, \[F={{10}^{-4}}N,\,m=1\,Am\] \[\therefore \] \[B=\frac{F}{m}=\frac{{{10}^{-4}}}{1}={{10}^{-4}}T\] Note: The force on positive magnetic charge is along the field and a force on a, negative magnetic charge is opposite to the field.
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