A) \[400\,\Omega \]
B) \[900\,\Omega \]
C) \[1100\,\Omega \]
D) \[1000\,\Omega \]
Correct Answer: B
Solution :
Resistance added to galvanometer is \[R=\frac{V}{{{i}_{g}}}-G\] or \[R=\frac{V}{{{i}_{g}}}-100\] \[\Rightarrow \] \[R+100=\frac{V}{{{i}_{g}}}\] and \[R+1000=\frac{2V}{{{i}_{g}}}-100\] \[\Rightarrow \] \[R+1100=\frac{2V}{{{i}_{g}}}\] ?(ii) Dividing Eq. (ii) by Eq, (i), we get \[\frac{R+1100}{R+100}=2\] or \[R+1100=2R+200\] or \[R=900\,\Omega \]You need to login to perform this action.
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