A) 35.25
B) 35.45
C) 36.25
D) 36.45
Correct Answer: B
Solution :
Key Idea: At. wt. of chlorine \[\text{=}\,\frac{\text{Abundance}\,\text{ }\!\!\times\!\!\text{ }\,\text{mass}\,\text{+}\,\text{Adundance}\,\text{ }\!\!\times\!\!\text{ }\,\text{mass}}{\text{100}}\] Given, abundance of \[\text{C}{{\text{l}}^{\text{35}}}\]isotope \[=75.53%\] Mass of \[C{{l}^{35}}\]isotope \[=34.97\] Abundance of \[C{{l}^{37}}\]isotope \[=24.47%\] Mass of \[C{{l}^{37}}\]isotope \[=36.95\] \[\therefore \] At. wt. of chlorine \[=\frac{34.97\times 75.53+24.47\times 36.95}{100}\] \[=\frac{3545.45}{100}\] \[=35.45\]You need to login to perform this action.
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