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BCECE Engineering BCECE Engineering Solved Paper-2001

  • question_answer
    A Solution is made up of 10 mL of \[\text{0}\text{.1}\,\text{N}\,\text{NaOH}\]and 10 mL of \[\text{0}\text{.05}\,\text{N}{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\text{.}\]The \[\text{pH}\]of solution is:

    A) 7                             

    B)        \[>7\]

    C)  \[<7\]                   

    D)         None of these

    Correct Answer: B

    Solution :

    Given,\[NaOH\,V=10\,mL,\,N=0.1\] \[{{H}_{2}}S{{O}_{4}}V=10\,mL\,N=0.05\] Milli equivalents of\[NaOH=10\times 0.1=1\] Milli equivalents of \[{{H}_{2}}S{{O}_{4}}=10\times 0.05=0.5\] \[\because \]\[0.05\] milli equivalents of \[{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\]neutralizes  \[0.05\]milli equivalents of \[NaOH\]. \[\therefore \] \[0.05\]milli equivalents of \[NaOH\] will remain in solution. \[\therefore \]Solution is basic. Basic solution has\[pH>7\]. \[\therefore \]pH of solution is more than 7.


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