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BCECE Engineering BCECE Engineering Solved Paper-2002

  • question_answer
    In the reaction, \[2C(s)+{{O}_{2}}(g)2CO\,(g)\] the partial pressure of CO and \[{{O}_{2}}\]is 8 atm and 4 atm respectively, then find its equilibrium constant:

    A) 16                                          

    B) 24

    C) 8                             

    D)        2

    Correct Answer: A

    Solution :

    Key Idea: Only gaseous products have partial pressure. Given \[{{p}_{CO}}=8\,\text{atm,}\,{{\text{p}}_{{{O}_{2}}}}=4\,\text{atm}\] \[2C\,(s)+{{O}_{2}}(g)2CO\,(g)\] For above equilibrium                 \[{{K}_{p}}=\frac{{{({{p}_{CO}})}^{2}}}{{{p}_{{{O}_{2}}}}}=\frac{8\times 8}{4}=16\,\text{atm}\]


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