BCECE Engineering BCECE Engineering Solved Paper-2002

  • question_answer
    On bombarding \[{{\,}_{7}}{{N}^{14}}\] with \[\alpha -\]particles, the nuclei of the product formed after the release of a proton is:

    A) \[{{\,}_{8}}{{O}^{17}}\]

    B) \[{{\,}_{8}}{{O}^{18}}\] 

    C)        \[{{\,}_{9}}{{F}^{7}}\]    

    D)        \[{{\,}_{9}}{{F}^{18}}\]

    Correct Answer: A

    Solution :

                                    Key Idea: (i) Sum of atomic numbers of reactants = Sum of atomic numbers of products. (ii) Sum of atomic masses of readouts = Sum of atomic masses of products.                 \[\underset{\text{nitrogen}}{\mathop{{{\,}_{7}}{{N}^{14}}}}\,+\,\underset{\alpha -\text{particle}}{\mathop{_{2}H{{e}^{4}}}}\,\xrightarrow{{}}{{\,}_{8}}{{O}^{17}}+\underset{\text{proton}}{\mathop{{{\,}_{1}}{{H}^{1}}}}\,\]


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