A) \[{{10}^{-7}}K\]
B) \[{{10}^{7}}K\]
C) \[{{10}^{-3}}K\]
D) \[5.86\,\times {{10}^{7}}K\]
Correct Answer: B
Solution :
Whens displacement law is given by \[{{\lambda }_{m}}T=\] constant (say b) Given, b = Wiens constant \[=2.93\times {{10}^{-3}}\,m-K\] \[{{\lambda }_{m}}=2.93\times {{10}^{-10}}m\] Substituting the values, we obtain \[T=\frac{b}{{{\lambda }_{m}}}\] \[=\frac{2.93\times {{10}^{-3}}}{2.93\times {{10}^{-10}}}\] \[={{10}^{7}}K\]
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