BCECE Engineering BCECE Engineering Solved Paper-2003

  • question_answer A piece of wax weighs 18.03 g in air. A piece of metal is found to weigh 17.03 g in water. It is tied to the wax and both together weigh 15.23 g in water. Then, the specific gravity of wax is:

    A) \[\frac{18.03}{17.03}\]                                  

    B)        \[\frac{17.03}{18.03}\]

    C)        \[\frac{18.03}{19.83}\]  

    D)        \[\frac{15.03}{17.83}\]

    Correct Answer: C

    Solution :

                                    Weight of wax in air, \[{{W}_{a}}=18.13g\] Weight of metal piece in water \[=17.03g\] Weight of metal piece and wax in water \[=15.23g\] Weight of wax in water                 \[{{W}_{w}}=15.23-17.03=-1.8g\] Therefore, specific gravity of wax \[\text{=}\,\,\frac{\text{weight}\,\text{of}\,\text{wax}\,\text{in}\,\text{air}}{\text{weight}\,\text{of}\,\text{wax}\,\text{in}\,\text{air-weight}\,\text{of}\,\text{wax}\,\text{in}\,\text{water}}\] \[=\frac{18.03}{18.03-(-1.8)}\] \[=\frac{18.03}{19.83}\]


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