• # question_answer A piece of wax weighs 18.03 g in air. A piece of metal is found to weigh 17.03 g in water. It is tied to the wax and both together weigh 15.23 g in water. Then, the specific gravity of wax is: A) $\frac{18.03}{17.03}$                                   B)        $\frac{17.03}{18.03}$ C)        $\frac{18.03}{19.83}$   D)        $\frac{15.03}{17.83}$

Weight of wax in air, ${{W}_{a}}=18.13g$ Weight of metal piece in water $=17.03g$ Weight of metal piece and wax in water $=15.23g$ Weight of wax in water                 ${{W}_{w}}=15.23-17.03=-1.8g$ Therefore, specific gravity of wax $\text{=}\,\,\frac{\text{weight}\,\text{of}\,\text{wax}\,\text{in}\,\text{air}}{\text{weight}\,\text{of}\,\text{wax}\,\text{in}\,\text{air-weight}\,\text{of}\,\text{wax}\,\text{in}\,\text{water}}$ $=\frac{18.03}{18.03-(-1.8)}$ $=\frac{18.03}{19.83}$