A) \[\frac{\pi }{2}\]
B) \[\frac{\pi }{4}\]
C) zero
D) nothing can be said
Correct Answer: C
Solution :
In a series LCR circuit, potential difference leads the current by an angle \[\text{o }\!\!|\!\!\text{ }\](let). \[\text{o }\!\!|\!\!\text{ }={{\tan }^{-1}}\left( \frac{{{X}_{L}}-{{X}_{C}}}{R} \right)\] or \[\text{o }\!\!|\!\!\text{ }={{\tan }^{-1}}\left( \frac{\omega L-\frac{1}{\omega C}}{R} \right)\] At resonance, \[{{X}_{L}}={{X}_{C}},\]i.e., \[\omega L=\frac{1}{\omega C}\] Hence, \[\text{o}|={{\tan }^{-1}}(0)=0\] Therefore, phase difference between current and voltage at resonance is zero.
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