A) \[\sqrt{{{K}_{sp}}}\]
B) \[{{({{K}_{sp}})}^{1/3}}\]
C) \[{{({{K}_{sp/4}})}^{1/3}}\]
D) \[{{(8{{K}_{sp}})}^{1/2}}\]
Correct Answer: C
Solution :
Let the solubility of \[PbC{{l}_{2}}=x\,mol/L\] \[\underset{x\,mol/L}{\mathop{PbC{{l}_{2}}}}\,\underset{x}{\mathop{P{{b}^{2+}}}}\,+\underset{2x}{\mathop{2C{{l}^{-}}}}\,\] \[{{K}_{sp}}=[P{{b}^{2+}}]{{[C{{l}^{-}}]}^{2}}\] or \[=(x)\times {{(2x)}^{2}}\] or \[=4{{x}^{3}}\] \[\therefore \] \[x=\sqrt[3]{\frac{{{K}_{sp}}}{4}}={{\left( \frac{{{K}_{sp}}}{4} \right)}^{1/3}}\]
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