BCECE Engineering BCECE Engineering Solved Paper-2003

  • question_answer
    When two conductors of charges and potentials \[{{C}_{1}},\,{{V}_{1}}\] and \[{{C}_{2}},\,{{V}_{2}}\] respectively are joined, the common potential will be:

    A)  \[\frac{{{V}_{1}}{{V}_{1}}+{{C}_{2}}{{V}_{2}}}{{{V}_{1}}+{{V}_{2}}}\]                     

    B)        \[\frac{{{C}_{1}}{{V}_{1}}^{2}+{{C}_{2}}{{V}_{2}}^{2}}{{{V}_{1}}^{2}+{{V}_{2}}^{2}}\]

    C)        \[{{C}_{1}}+{{C}_{2}}\]                  

    D)        \[\frac{{{C}_{1}}{{V}_{1}}+{{C}_{2}}{{V}_{2}}^{2}}{{{C}_{1}}+{{C}_{2}}}\]

    Correct Answer: D

    Solution :

    When two conductors of capacities \[{{C}_{1}}\]and \[{{C}_{2}}\] and potentials\[{{V}_{1}}\] and \[{{V}_{2}}\]are connected by a conducting wire, charge redistributes in these conductors till potential of both the  conductors become equal, known as common potential. Common potential \[=\frac{\text{net}\,\text{charge}}{\text{total}\,\text{capacity}}\]                 i.e.,                        \[V=\frac{{{q}_{1}}+{{q}_{2}}}{{{C}_{1}}+{{C}_{2}}}\]                 or                            \[V=\frac{{{C}_{1}}{{V}_{1}}+{{C}_{2}}{{V}_{2}}}{{{C}_{1}}+{{C}_{2}}}\]


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