question_answer

In the reaction, \[HCHO+N{{H}_{3}}\xrightarrow{{}}X,X\]is:

A) meta-formaldehyde                                

B) para-formaldehyde                           

C) urotropine          

D)                                 none of the above                              

Correct Answer: C

Solution :

Key Idea: Formaldehyde reacts with \[\text{N}{{\text{H}}_{\text{3}}}\]to form urotropine which is used as medicine to cure urinary infections. \[\underset{\text{formaldehyde}}{\mathop{6HCHO}}\,\,+\underset{\text{ammonia}}{\mathop{4\,N{{H}_{3}}}}\,\xrightarrow{{}}\underset{\begin{smallmatrix}  \,\,\,\,\,\,\,\,\,\text{hexamethylene} \\  \text{tetramine}\,\text{or}\,\text{urotropine} \end{smallmatrix}}{\mathop{{{(C{{H}_{2}})}_{6}}{{N}_{4}}}}\,\] \[\underset{\text{formaldehyde}}{\mathop{\underset{(h)}{\mathop{HCHO}}\,}}\,\xrightarrow{37\,K}\underset{\text{paraformaldehyde}}{\mathop{{{(C{{H}_{2}}O)}_{n}}{{N}_{4}}}}\,\] \[3HCHO\xrightarrow[\text{stand}]{\text{allowed}\,\text{to}}\]   \[\therefore \]  (c) is the correct answer.