BCECE Engineering BCECE Engineering Solved Paper-2004

  • question_answer
    Water falls from a height 500 m. The rise in temperature of water at bottom if whole of                the energy remains in water, will be : (specific heat of water is c = 4.2 kJ/kg)

    A) \[0.23{}^\circ C\]                             

    B)        \[1.16{}^\circ C\]

    C)        \[0.96{}^\circ C\]                             

    D)        \[1.02{}^\circ C\]

    Correct Answer: B

    Solution :

    Key Idea: Potential energy = increase in heat of water. From law of conservation of energy, we know that energy can neither be created nor destroyed, it remains conserved. When water falls from a height, it has potential energy \[(mgh),\] this is used in heating up the water \[(mc\Delta \theta ).\] Hence, we have \[mgh=mc\Delta \theta \] \[\Rightarrow \]               \[\Delta \theta =\frac{gh}{c}\] \[=\frac{9.8\times 500}{4.2\times {{10}^{3}}}=1.16{{\,}^{o}}C\]


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