A) \[\frac{y-1}{y}\]
B) \[\frac{1-y}{y}\]
C) \[\frac{y}{1-y}\]
D) none of these
Correct Answer: A
Solution :
Key Idea: Given series is a GP series whose common ratio is \[x\] We have \[y=1+x+{{x}^{2}}+{{x}^{3}}+....\infty \] \[y=\frac{1}{1-x}\] \[\Rightarrow \] \[y(1-x)=1\] \[\Rightarrow \] \[xy=y-1\] \[\Rightarrow \] \[x=\frac{y-1}{y}\] Note: The sum of infinite series is only possible when the common ratio is lying between\[-1\]to 1.
You need to login to perform this action.
You will be redirected in
3 sec
