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BCECE Engineering BCECE Engineering Solved Paper-2004

  • question_answer
    If \[\sin A=\sin B\]and \[\cos A=\cos B,\]then A is equal to:

    A) \[2n\pi +B\]       

    B)         \[2n\pi -B\]       

    C)         \[n\pi +B\]        

    D)         \[n\pi +B{{(-1)}^{n}}B\]

    Correct Answer: A

    Solution :

    Since sin A = sin B \[\Rightarrow \]    \[~A=B\]and\[A=\pi -B\]                           ...(i) and        \[cos\,A=cos\,B\] \[\Rightarrow \]       \[A=B\]and\[A=2\pi -B\]       ...(ii) From Eqs. (i) and (ii) \[\Rightarrow \]               \[A=2n\pi +B\]


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