BCECE Engineering BCECE Engineering Solved Paper-2004

  • question_answer
    The area of the circle whose centre is at (1, 2) and passing through (4, 6) is

    A) \[5\pi \,\text{sq}\,\text{unit}\]       

    B)        \[10\pi \,\text{sq}\,\text{unit}\]              

    C)         \[25\,\pi \,\,\text{sq}\,\text{unit}\]     

    D)         none of these

    Correct Answer: C

    Solution :

    Area of circle \[=\pi {{r}^{2}}\] The centre of circle is (1, 2) and point on the circle is (4, 6). Radius = distance between centre and point on. Circle \[=\sqrt{{{(4-1)}^{2}}+{{(6-2)}^{2}}}=\sqrt{{{3}^{2}}+{{4}^{2}}}\] \[=5\] As we know Radius of circle \[=\pi {{r}^{2}}\] \[=\pi {{(5)}^{2}}\] \[=25\,\pi \,\text{sq}\,\text{unit}\]


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