A) \[\frac{1}{\sqrt{2}}\]
B) \[\sqrt{2}\]
C) \[\frac{1}{2}\]
D) 2
Correct Answer: A
Solution :
Key Idea: The eccentricity of rectangular hyperbola is \[\sqrt{2}.\] Let the equation of rectangular hyperbola be \[{{x}^{2}}-{{y}^{2}}={{a}^{2}}.\] As we know, \[e=\sqrt{1+\frac{{{b}^{2}}}{{{a}^{2}}}}=\sqrt{1+\frac{{{a}^{2}}}{{{a}^{2}}}}\] \[[\because \,{{b}^{2}}={{a}^{2}}]\] \[\therefore \]The reciprocal of the eccentricity is\[\frac{1}{\sqrt{2}}.\]
You need to login to perform this action.
You will be redirected in
3 sec
