A) 125 m/s
B) 250 m/s
C) 500 m/s
D) 1000 m/s
Correct Answer: C
Solution :
A normal mode of an oscillating system is a motion in which all particles of the system move sinusoidally with the same frequency. In general, \[pth\]mode of a string fixed at ends has frequency. \[n=\frac{pv}{2l}\] \[p=1,2,3..\] where\[v\] is velocity of wave and I is length of string. In fourth normal mode, \[p=4\] \[\therefore \,\] \[n=\frac{4v}{2l}\] Given, \[n=500\,Hz,l=2\,m\] Hence, \[500\,=\frac{4v}{2\times 2}\] or \[v=\frac{500\times 4}{4}=500\,m/s\]You need to login to perform this action.
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