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BCECE Engineering BCECE Engineering Solved Paper-2005

  • question_answer
    A reaction \[A\xrightarrow{{}}B\]follows a second order kinetic. Doubling the concentration of A will increase the rate of formation of B by a factor of:

    A) 1/4                                        

    B) 4

    C) 1/2                        

    D)        2

    Correct Answer: B

    Solution :

    Key Idea: For second order reaction \[r=k{{[A]}^{2}}\]                             ?(i) When concentration of A (reactant) is doubled \[r=k{{[2A]}^{2}}\] \[r=4k\,{{[A]}^{2}}\]                                       ?(ii) Comparing Eqs. (i) and (ii) \[r=4\,r\]


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