A) \[{{K}_{2}}S{{O}_{4}}\]
B) \[NaCl\]
C) Urea
D) Glucose
Correct Answer: A
Solution :
Key Idea: Depression in freezing point is a colligative property. It depends on no. of particles. More the number of particles, more will be depression in freezing point. (a)\[{{K}_{2}}S{{O}_{4}}\xrightarrow{{}}2{{K}^{+}}+SO_{4}^{2-}\] If give 3 particles (b) \[NaCl\xrightarrow{{}}N{{a}^{+}}+C{{l}^{-}}\] It gives 2 particles (c) Urea\[\xrightarrow{{}}\]No dissociation. (d) Glucose\[\xrightarrow{{}}\]No dissociation. \[\because \]\[{{K}_{2}}S{{O}_{4}}\]produces maximum number of particles \[\therefore \] \[{{K}_{2}}S{{O}_{4}}\]has maximum depression in freezing point.
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