A) \[6\,\,V{{m}^{-1}}\]
B) \[60\,\,V{{m}^{-1}}\]
C) \[\frac{1}{6}\,V{{m}^{-1}}\]
D) none of these
Correct Answer: B
Solution :
We can write the electric and magnetic fields as sinusoidal functions of position \[x\] and time t. \[E={{E}_{0}}\sin (kx-\omega t)\] \[B={{B}_{0}}\sin (kx-\omega t)\] In this \[{{E}_{0}}\]and \[{{B}_{0}}\]are the amplitudes of the fields. Further \[c=\frac{{{E}_{0}}}{{{B}_{0}}}.\] or \[{{E}_{0}}={{B}_{0}}c\] Given, \[{{B}_{0}}=2\times {{10}^{-7}}T,c=3\times {{10}^{8}}\,m/s\] we have \[{{E}_{0}}=2\times {{10}^{-7}}\times 3\times {{10}^{8}}=60\,V{{m}^{-1}}\]
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