A) \[KCl{{O}_{4}}\]
B) \[KCl{{O}_{3}}\]
C) \[KCl{{O}_{2}}\]
D) \[KClO\]
Correct Answer: B
Solution :
When chlorine is passed into hot concentrated solution of KOH, potassium chlorate is formed. \[6KOH+3C{{l}_{2}}\xrightarrow{{}}5KCl+\underset{\text{potassium}\,\text{chlorate}}{\mathop{KCl{{O}_{3}}}}\,+3{{H}_{2}}O\]
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