A) \[0.72,0.71\]
B) \[~0.72,1.6\]
C) \[1.6,\text{ }1.58\]
D) \[~0.71,\text{ }0.72\]
Correct Answer: B
Solution :
Atomic radii decrease in a period from left to right, hence, fluorine has a very less atonic radii (covalent atomic radii\[=0.72\overset{\text{o}}{\mathop{\text{A}}}\,\]). But mat gases (like Ne) are monoatomic gases, hence, their covalent atomic radii cannot be found out In fact, their calculated atomic radii is the m der Waals radii, which is found almost double to covalent radii, hence, the van der Waals radius of neon (Ne) is about \[1.60\overset{\text{o}}{\mathop{\text{A}}}\,.\]
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