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BCECE Engineering BCECE Engineering Solved Paper-2006

  • question_answer
    For \[CaC{{O}_{3}}(s)CaO(s)+C{{O}_{2}}(g)\]at \[927{{\,}^{o}}C,\]\[\Delta H=176\,kJ\,\text{mol}\,;\]then \[\Delta E\]is:

    A)  180 kJ                                  

    B)  186.4 kJ

    C)  166.0 kJ              

    D)         160 kJ

    Correct Answer: C

    Solution :

    \[CaC{{O}_{3}}(g)CaO(s)+C{{O}_{2}}(g)\] \[(\Delta {{n}_{g}}=1-0=1)\] We know that,                                 \[\Delta H=\Delta E+\Delta {{n}_{g}}RT\]                 \[176=\Delta E+1\times 8.31\times {{10}^{-3}}\times (273+927)\]                 \[\therefore \]  \[\Delta \Epsilon =176-8.31\times {{10}^{-3}}\times 1200\]                                 \[=176-9.97=166.03\,kJ\]


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