A) 4 times that of He
B) 2 times that of He
C) 0.35 times that of He
D) 8 times that of He
Correct Answer: C
Solution :
According to Grahams law of diffusion \[\frac{{{r}_{{{O}_{2}}}}}{{{r}_{He}}}=\sqrt{\frac{{{M}_{He}}}{{{M}_{{{O}_{2}}}}}}\] or \[=\sqrt{\frac{4}{32}}=\frac{1}{2.83}\] \[\therefore \] \[{{r}_{{{O}_{2}}}}=0.35\,{{r}_{He}}\]
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