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BCECE Engineering BCECE Engineering Solved Paper-2007

  • question_answer
    The    equation    of    a    line    is\[6x-2=3y-1=2z-2.\]The direction ratios of the line are

    A)  1, 2, 3  

    B)         1, 1, 1  

    C)         \[\frac{1}{3},\frac{1}{3},\frac{1}{3}\]     

    D)         \[\frac{1}{3},\frac{-1}{3},\frac{1}{3}\]

    Correct Answer: A

    Solution :

    The given equation is \[6x-2=3y-1=2z-2\] \[\Rightarrow \]\[\frac{x-\frac{1}{3}}{1}=y\frac{y-\frac{1}{3}}{2}=\frac{z-1}{3}\] This shows that DRs of given equation are (1, 2, 3).


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