A) \[\{125\}\]
B) \[\{8\}\]
C) \[\phi \]
D) \[\text{ }\!\!\{\!\!\text{ 125,8 }\!\!\}\!\!\text{ }\]
Correct Answer: D
Solution :
Given equation can be rewritten as \[{{({{x}^{1/3}})}^{2}}-7({{x}^{1/3}})+10=0\] Let \[\alpha ={{x}^{1/3}}\]then I t reduces to \[{{\alpha }^{2}}-7\alpha +10=0\] \[\Rightarrow \]\[(\alpha -5)(\alpha -2)=0\Rightarrow \alpha =5,2\] \[\therefore \]\[{{\alpha }^{3}}=x\Rightarrow x=125\]and 8 \[\cos e{{c}^{-1}}(sec\alpha )+co{{t}^{-1}}(tan\alpha )\]
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